2178번: 미로 탐색
첫째 줄에 두 정수 N, M(2 ≤ N, M ≤ 100)이 주어진다. 다음 N개의 줄에는 M개의 정수로 미로가 주어진다. 각각의 수들은 붙어서 입력으로 주어진다.
www.acmicpc.net
접근 : 최단경로! bfs
Javascript
let input = require("fs")
.readFileSync("input.txt") //"/dev/stdin"
.toString()
.split("\n")
.map((val) => val.trim());
function solution(input) {
//input
let [n, m] = input
.shift()
.split(" ")
.map((v) => +v);
let graph = [];
for (let i = 0; i < n; i++) {
graph.push(input.shift().split(""));
}
let visit = new Array(n).fill().map(() => new Array(m).fill(-1));
let answer = BFS(0, 0, graph, visit, n, m);
console.log(answer);
}
function BFS(x, y, graph, visit, n, m) {
let dx = [0, 1, 0, -1];
let dy = [1, 0, -1, 0];
let queue = [];
visit[x][y] = 0;
queue.push([x, y]);
while (queue.length !== 0) {
let [curX, curY] = queue.shift();
for (let dir = 0; dir < 4; dir++) {
let nx = curX + dx[dir];
let ny = curY + dy[dir];
if (nx < 0 || nx >= n || ny < 0 || ny >= m) continue;
if (visit[nx][ny] >= 0 || graph[nx][ny] === "0") continue;
visit[nx][ny] = visit[curX][curY] + 1;
queue.push([nx, ny]);
}
}
console.log(visit);
return visit[n - 1][m - 1] + 1;
}
solution(input);
c++
#include <bits/stdc++.h>
using namespace std;
#define X first
#define Y second
string graph[102];
int vis[102][102];
int n,m;
int dx[4] = {0,1,0,-1};
int dy[4] = {1,0,-1,0};
int BFS(int x,int y){
queue<pair<int,int>> Q;
vis[x][y] = 0;
Q.push({x,y});
while(!Q.empty()){
pair<int,int> cur = Q.front();
Q.pop();
for(int dir=0;dir<4;dir++){
int nx = cur.X+dx[dir];
int ny = cur.Y+dy[dir];
if(nx < 0 || nx >= n || ny < 0 || ny >= m) continue;
if(vis[nx][ny]>=0||graph[nx][ny]!='1') continue;
vis[nx][ny] = vis[cur.X][cur.Y]+1;
Q.push({nx,ny});
}
}
return vis[n-1][m-1]+1;
}
int main()
{
freopen("input.txt", "r", stdin); //제출 시 삭제
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin>>n>>m;
for(int i=0;i<n;i++){
cin>>graph[i];
}
for(int i=0;i<n;i++){
fill(vis[i],vis[i]+m,-1);
}
int answer = BFS(0,0);
cout<<answer<<"\n";
}
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